Determine which JAR file a class is from

Determine which JAR file a class is from

I am not in front of an IDE right now, just looking at the API specs.

CodeSource src = MyClass.class.getProtectionDomain().getCodeSource();
if (src != null) {
    URL jar = src.getLocation();
}

I want to determine which JAR file a class is from. Is this the way to do it?

Yes. It works for all classes except classes loaded by bootstrap classloader. The other way to determine is:

Class klass = String.class;
URL location = klass.getResource('/' + klass.getName().replace('.', '/') + ".class");

notnoop이 지적한 바와 같이klass.getResource()메소드는 클래스 파일 자체의 위치를 반환한다.예를 들면 다음과 같다.

jar:file:/jdk/jre/lib/rt.jar!/java/lang/String.class
file:/projects/classes/pkg/MyClass$1.class

그getProtectionDomain().getCodeSource().getLocation()메소드는 jar 파일 또는 CLASSPATH의 위치를 반환함

file:/Users/home/java/libs/ejb3-persistence-1.0.2.GA.jar
file:/projects/classes

체크아웃LiveInjector.findPathJar()롬복 패처로부터. 파일이 실제로 항아리 안에 살지 않는 특별한 경우라는 점에 유의하십시오. 그리고 당신은 그것을 바꾸고 싶을지도 모른다.

/**
 * If the provided class has been loaded from a jar file that is on the local file system, will find the absolute path to that jar file.
 * 
 * @param context The jar file that contained the class file that represents this class will be found. Specify {@code null} to let {@code LiveInjector}
 *                find its own jar.
 * @throws IllegalStateException If the specified class was loaded from a directory or in some other way (such as via HTTP, from a database, or some
 *                               other custom classloading device).
 */
public static String findPathJar(Class<?> context) throws IllegalStateException {
    if (context == null) context = LiveInjector.class;
    String rawName = context.getName();
    String classFileName;
    /* rawName is something like package.name.ContainingClass$ClassName. We need to turn this into ContainingClass$ClassName.class. */ {
        int idx = rawName.lastIndexOf('.');
        classFileName = (idx == -1 ? rawName : rawName.substring(idx+1)) + ".class";
    }

    String uri = context.getResource(classFileName).toString();
    if (uri.startsWith("file:")) throw new IllegalStateException("This class has been loaded from a directory and not from a jar file.");
    if (!uri.startsWith("jar:file:")) {
        int idx = uri.indexOf(':');
        String protocol = idx == -1 ? "(unknown)" : uri.substring(0, idx);
        throw new IllegalStateException("This class has been loaded remotely via the " + protocol +
                " protocol. Only loading from a jar on the local file system is supported.");
    }

    int idx = uri.indexOf('!');
    //As far as I know, the if statement below can't ever trigger, so it's more of a sanity check thing.
    if (idx == -1) throw new IllegalStateException("You appear to have loaded this class from a local jar file, but I can't make sense of the URL!");

    try {
        String fileName = URLDecoder.decode(uri.substring("jar:file:".length(), idx), Charset.defaultCharset().name());
        return new File(fileName).getAbsolutePath();
    } catch (UnsupportedEncodingException e) {
        throw new InternalError("default charset doesn't exist. Your VM is borked.");
    }
}

Use

String path = <Any of your class within the jar>.class.getProtectionDomain().getCodeSource().getLocation().getPath(); 

If this contains multiple entries then do some substring operation.

private String resourceLookup(String lookupResourceName) {



    try {

        if (lookupResourceName == null || lookupResourceName.length()==0) {
            return "";
        }
        // "/java/lang/String.class"

        // Check if entered data was in java class name format
        if (lookupResourceName.indexOf("/")==-1) {
            lookupResourceName = lookupResourceName.replaceAll("[.]", "/");
            lookupResourceName =  "/" + lookupResourceName + ".class";
        }

        URL url = this.getClass().getResource(lookupResourceName);
        if (url == null) {
            return("Unable to locate resource "+ lookupResourceName);

        }

        String resourceUrl = url.toExternalForm();

        Pattern pattern =
            Pattern.compile("(zip:|jar:file:/)(.*)!/(.*)", Pattern.CASE_INSENSITIVE);

        String jarFilename = null;
        String resourceFilename = null;
        Matcher m = pattern.matcher(resourceUrl);
        if (m.find()) {
            jarFilename = m.group(2);
            resourceFilename = m.group(3);
        } else {
            return "Unable to parse URL: "+ resourceUrl;

        }

        if (!jarFilename.startsWith("C:") ){
          jarFilename = "/"+jarFilename;  // make absolute path on Linux
        }

        File file = new File(jarFilename);
        Long jarSize=null;
        Date jarDate=null;
        Long resourceSize=null;
        Date resourceDate=null;
        if (file.exists() && file.isFile()) {

            jarSize = file.length();
            jarDate = new Date(file.lastModified());

            try {
                JarFile jarFile = new JarFile(file, false);
                ZipEntry entry = jarFile.getEntry(resourceFilename);
                resourceSize = entry.getSize();
                resourceDate = new Date(entry.getTime());
            } catch (Throwable e) {
                return ("Unable to open JAR" + jarFilename + "   "+resourceUrl +"\n"+e.getMessage());

            }

           return "\nresource: "+resourceFilename+"\njar: "+jarFilename + "  \nJarSize: " +jarSize+"  \nJarDate: " +jarDate.toString()+"  \nresourceSize: " +resourceSize+"  \nresourceDate: " +resourceDate.toString()+"\n";


        } else {
            return("Unable to load jar:" + jarFilename+ "  \nUrl: " +resourceUrl);

        }
    } catch (Exception e){
        return e.getMessage();
    }


}

Linux에서는 작은 스크립트를 사용하여 클래스가 어느 항아리에 있는지 찾을 수 있도록 도와주고 있다.find -exec:

findclass.sh:

unzip -l "$1" 2>/dev/null | grep $2 >/dev/null 2>&1 && echo "$1"

기본적으로, 항아리가 지퍼로 되어 있기 때문에unzip -l클래스 리소스 목록을 인쇄하므로 변환하십시오..로/. 스크립트에서 대체를 수행할 수 있는 경우tr, 하지만 대본에 전화할 때 직접 하는 것은 그리 어려운 일이 아니다.

그 아이디어는find모든 항아리를 찾기 위한 수업 경로의 뿌리에 있는findclass.sh성냥을 찾기 위해 발견된 모든 항아리들 위에

It doesn't handle multi-directories, but if you carefully choose the root you can get it to work.

이제 클래스가 들어 있는 항아리를 찾으십시오.org.apache.commons.lang3.RandomUtils프로젝트 관리(...):

$ find ~/.m2/repository/ -type f -name '*.jar' -exec findclass.sh {} org/apache/commons/lang3/RandomUtils \;

.m2/repository/org/apache/commons/commons-lang3/3.7/commons-lang3-3.7.jar
.m2/repository/org/apache/commons/commons-lang3/3.6/commons-lang3-3.6.jar
.m2/repository/org/apache/commons/commons-lang3/3.6/commons-lang3-3.6-sources.jar
$

ReferenceURL : https://stackoverflow.com/questions/1983839/determine-which-jar-file-a-class-is-from